solution: In the above problem, acceleration of a particle is (a)=10m/s2 time=5s final velocity=50m/s but it is moving with uniform acceleration. v=u+at 50=u+10*5 u=0m/s i.e it starts with zero initial vvelocity then we have to calculate velocity at 4s for this a=4m/s2 t=4s u=0m/s v=0+10*4 v=40m/s the velocity at 4s is 40m/s.
solution: final velocity:25m/s time :2s a=4m/s2 then, the formula we have v=u+at 25=u+4*2 25-8=u u=17m/s The displacement S=ut+1/2at2 S=17(2)+1/2(4)(2)(2) S=34+8 S=42m The displacement of the body is 42m
solution: u=10m/s a=a v=30m/s S=4km=4000m v2-u2=2as 900-100=2a*4000 800=8000a a=0.1m/s2 then, v=u +at 30=10+0.1*t 30-10=0.1t 20=0.1t t=200s The time taken is 200s.
solution: Given information, u=5m/s v=10m/s s=50m v2-u2=2as 100-25=2*a*s 75=2*a*50 75=100a a=0.75m/s2 The acceleration of the body is 0.75m/s2
Given information, u=10m/s v=20m/s t=2s v=u + at 20=10+2a 20-10=2a 10=2a a=5 m/s2 The acceleration of the body is 5m/s2
solution: just simple ,compare with v=u+at u=0.6m/s a=-0.3m/s2
solution: Given information: u =12m/s v=6m/s t=3s we have formula: v= u+ at a=v-u/t a=6-12/3 a=-2m/s2 by this answer, we can say the body is in decelarated motion.
Solution: Given information u=2m/s a=1m/s2 t=10sec We have the formula V=u+at V=2+1*10 V=12m/s.
An object can store energy as the result of its position. For example, the heavy ball of a demolition machine is storing energy when it is held at an elevated position. This stored energy of position is referred to as potential energy. Similarly, a drawn bow is able to store energy as the result of …
