6.A car moving with a velocity of 10m/s and with a uniform acceleration gains a velocity of 30m/s after travelling a distance of 4km.The time taken is

solution:

u=10m/s

a=a

v=30m/s

S=4km=4000m

v2-u2=2as

900-100=2a*4000

800=8000a

a=0.1m/s2

then,

v=u +at

30=10+0.1*t

30-10=0.1t

20=0.1t

t=200s

The time taken is 200s.

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