26.A particle is projected vertically up with speed of 10m/s. The time after which it will pass through the point 3.2m above the point of projection Leave a Comment / By vibgyor4u.com / 19 January 2024 solution: The particle projected with (u)=10m/s H=3.2M a=10m/s2 S= ut +(1/2)at2 3.2=10t-1/2x10xt2 3.2=10t-5t2 t=0.4s Views: 84
