25.A body falls freely from the top of tower. It covers 36 % of total height in the last second, before striking the ground level, the height of the tower is

solution:

a body falls freely from the tower ,it means it has initial velocity is zero.

we have formula ,The total time taken is ‘t’

S= ut +(1/2)at²

Total height (H)=(1/2)g(t)² …………. (1)

For remaining 64% covered in (t-1) seconds

(64/100)H=1/2g(t-1)² ……………….(2)

Equation (1)/Equation(2)

1/(64/100)=(t)² /(t-1)²

(t/t-1)=10/8

t=5sec

then, Total height (H)=(1/2)g(t)² =(1/2)*10*5*5

H =125m