solution:
a body projected with velocity (u)=49m/s
projected with an angle =60 degrees
H=(u2sin2Ɵ)/2g
H=(492sin260)/2g
H=(49*49*3/4)/2*9.8
H=91.875m
21.A body is projected with a velocity of 49m/s at an angle 60 degrees with the horizontal. It reaches a maximum height of