solution: u=10m/s a=a v=30m/s S=4km=4000m v2-u2=2as 900-100=2a*4000 800=8000a a=0.1m/s2 then, v=u +at 30=10+0.1*t 30-10=0.1t 20=0.1t t=200s The time taken is 200s.
solution: Given information, u=5m/s v=10m/s s=50m v2-u2=2as 100-25=2*a*s 75=2*a*50 75=100a a=0.75m/s2 The acceleration of the body is 0.75m/s2
Given information, u=10m/s v=20m/s t=2s v=u + at 20=10+2a 20-10=2a 10=2a a=5 m/s2 The acceleration of the body is 5m/s2
solution: just simple ,compare with v=u+at u=0.6m/s a=-0.3m/s2
solution: Given information: u =12m/s v=6m/s t=3s we have formula: v= u+ at a=v-u/t a=6-12/3 a=-2m/s2 by this answer, we can say the body is in decelarated motion.
